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Abstract Algebra Dummit Foote Solutions Pdf Chapter 3 16 "A, B, C are the only numbers whose sum is equal to zero." That's not true. 1 and 2 are. The best way to understand this is to use word problems. Let's start with an example in which the three numbers are A = 20, B = 10, and C = 15. This is an example of a mathematical sequence. The sequence begins with the first number, A, and continues with the second number, B, and concludes with the third number, C. Let's say that we need to find A2 + B2 + C2. To find A2 + B2 + C2 you can first multiply each of the terms by 2: Now it gets trickier since some expressions are easier to multiply than others (there are more numbers that can be multiplied by any given number). To multiply A, B, and C you have to multiply the first term by A × A, the second term by B × B, and the third term by C × C. This is where we get into word problems. If we take out the word "if" we can say: "Find A2 + B2 + C2", and we get: 2A + 4B + 6C = 26. But if we put "if" back in we get: 26 = 4A + 6B + 10C. This is because the "if" gives us a problem that can be solved with an equation or word problem without needing to solve it algebraically. This is Called a Word Problem. Word problems are a type of mathematical problem where a real-world situation is described by a problem. In these problems, it is often not possible to solve the problem analytically (that is, with equations), so translation into an algebraic equation may not be possible. Word problems typically involve some unknown quantity, which must be calculated or estimated.Example 1: A bus can hold fifty people. If there are twice as many boys as girls on the bus, how many girls are on the bus? The solution to this word problem involves counting both boys and girls twice because they are counted in pairs. The solution is: 50(2) + 150 = 250. Example 2: A man has a bicycle of the same length as the bus. In addition, he has a ball which weighs three times as much as the bike. How many girls are on the bus? A similar approach is used to solve this, but with different quantities being counted instead of pairs of things being counted. The solution to this problem is: 150(3) + 50 = 250. Example 3: There are four people in a village – two men and two women – and everyone's shoe size is equal. cfa1e77820
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